10=(t^2-t)/2

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Solution for 10=(t^2-t)/2 equation: 


t in (-oo:+oo)

10 = (t^2-t)/2 // - (t^2-t)/2

10-((t^2-t)/2) = 0

(-1*(t^2-t))/2+10 = 0

(-1*(t^2-t))/2+(2*10)/2 = 0

2*10-1*(t^2-t) = 0

t-t^2+20 = 0

t-t^2+20 = 0

t-t^2+20 = 0

DELTA = 1^2-(-1*4*20)

DELTA = 81

DELTA > 0

t = (81^(1/2)-1)/(-1*2) or t = (-81^(1/2)-1)/(-1*2)

t = -4 or t = 5

(t+4)*(t-5) = 0

((t+4)*(t-5))/2 = 0

((t+4)*(t-5))/2 = 0 // * 2

(t+4)*(t-5) = 0

( t+4 )

t+4 = 0 // - 4

t = -4

( t-5 )

t-5 = 0 // + 5

t = 5

t in { -4, 5 }

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